Keyword | CPC | PCC | Volume | Score |
---|---|---|---|---|

find the cube root of 512 ncert maths | 1.37 | 0.5 | 4863 | 48 |

1 Step 1: Find the prime factors of 512#N#512 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 2 Step 2: Pair the factors of 512 in a group of three, such that they form cubes.#N#512 = (2 × 2 × 2) × (2 × 2 × 2) × (2 × 2... 3 Step 3: Now, we will apply cube root on both the sides to take out the factor (in cubes) as a single term. More ...

It is not easy to find the cube root of 2. With the help of the long division method, it is possible to find the cube roots for non-perfect cube numbers. The approximate value of the ∛2 is 1.260.

∴ 3 is the unit digit of the cube root of 12167 We know 2 3 = 8 and 3 3 = 27 , 8 > 12 > 27. Thus, 2 is taken as ten digit of cube root.

Cube root of 2 is approximately equal to (1 + 1+2)/3 = 4/3 = 1.333.. Again 4 is a number, which is not a perfect cube. If we factorise it, we get: Hence, we can see, we cannot find the cube root by simple factorisation here. The actual value of ∛4 is 1.587, which is approximately equal to 1.67.